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Question

Chemistry Question on Structure of atom

If the de-Broglie wavelength of a particle of mass mm is 100100 times its velocity then its value in terms of its mass (m)(m) and Plants constant (h)(h) is

A

110m/h\frac{1}{10}\sqrt{m/h}

B

10h/m10\sqrt{h/m}

C

110h/m\frac{1}{10}\sqrt{h/m}

D

10m/h10\sqrt{m/h}

Answer

10h/m10\sqrt{h/m}

Explanation

Solution

Let the velocity of the particle =v=v
\therefore Wavelength (λ)(\lambda ) of the particle
=100v=100\,v or v=λ100v=\frac{\lambda }{100}
de-Broglie relationship is λ=hm.v\lambda =\frac{h}{m.v}
λ=h×100m.λ\lambda =\frac{h\times 100}{m.\lambda }
or λ2=h×100m{{\lambda }^{2}}=\frac{h\times 100}{m}
λ=10hm\lambda =10\sqrt{\frac{h}{m}}