Question

If the coordinates of the vertices of the triangle ABC be

(–1, 6), (–3, –9) and (5, –8) respectively, then the equation of the median through C is-

• A. 13x –14y –47 = 0
• B. 13x –14y + 47 = 0
• C. 13x + 14y + 47 = 0
• D. 13x + 14y –47 = 0

Answer 1

Answer: (C)

13x + 14y + 47 = 0

Answer 2

Mid point of AB $\left( - 2 , \frac { - 3 } { 2 } \right)$

Equation of median CD

y – y₁ = (x – x₁)

y + $\frac { 3 } { 2 }$= $\frac { - 8 + 3 / 2 } { 5 + 2 }$(x + 2)

13x + 14y + 47 = 0

Equation of median CD

y – y₁ = (x – x₁)

y + $\frac { 3 } { 2 }$= $\frac { - 8 + 3 / 2 } { 5 + 2 }$(x + 2)

13x + 14y + 47 = 0