Question

If the coordinates of the points A, B, C be (– 1, 5), (0, 0) and (2, 2) respectively and D be the middle point of BC, then the equation of the perpendicular drawn from B to the line AD is.

• A. $x + 2 y = 0$
• B. $2 x + y = 0$
• C. $x - 2 y = 0$
• D. $2 x - y = 0$

Answer 1

Answer: (C)

$x - 2 y = 0$

Answer 2

Here D(1, 1) therefore equation of line AD is given by $2 x + y - 3 = 0$. Thus the line perpendicular to AD is $x - 2 y + k = 0$and it passes through B, so $k = 0$ . Hence required equation is $x - 2 y = 0$ .