Question
Question: If the coordinates of one end of the diameter of the circle \(x ^ { 2 } + y ^ { 2 } - 8 x - 4 y + c ...
If the coordinates of one end of the diameter of the circle x2+y2−8x−4y+c=0 are (–3, 2), then the coordinates of other end are.
A
(5, 3)
B
(6, 2)
C
(1, –8)
D
(11, 2)
Answer
(11, 2)
Explanation
Solution
Obviously the centre of the circle is (4, 2) which should be the middle point of the ends of diameter.
Hence the other end is (11, 2).