Question
Question: If the coordinates of a variable point 'P' be \( \left( t+\dfrac{1}{t},t-\dfrac{1}{t} \right) \) , w...
If the coordinates of a variable point 'P' be (t+t1,t−t1) , where 't' is a
variable quantity, then find the locus of 'P'.
Solution
Write two equations of x and y in terms of t, and try to eliminate t from them by performing addition/subtraction or other mathematical operations.
The final equation in terms of the variables x and y is the required locus of the point P.
Observe that (a+b)2−(a−b)2=4ab . How can we use this to help eliminate it?
Complete step by step solution:
The coordinates of the point P are given to be (t+t1,t−t1) .
Therefore:
x=t+t1 ... (1)
y=t−t1 ... (2)
Squaring both the equations, we get:
x2=(t+t1)2
⇒ x2=t2+2×t×t1+t21
⇒ x2=t2+t21+2 ... (3)
And, y2=(t−t1)2
⇒ y2=t2−2×t×t1+t21
⇒ y2=t2+t21−2 ... (4)
Subtracting equation (4) from equation (3), we get:
x2−y2=4 , which is the required locus of the point P.
Note: It can also be added that the equation x2−y2=4 represents a hyperbola with vertices at (±2, 0) and center at the origin (0, 0) .
In geometry, a locus (plural: loci) (Latin word for "place", "location") is a set of all points (commonly, a line, a line segment, a curve or a surface), whose location satisfies or is determined by one or more specified conditions.
In other words, the set of the points that satisfy some property is often called the locus of a point satisfying this property.
e.g. The set of points equidistant from two points is a perpendicular bisector to the line segment connecting the two points.
A parametric equation defines a group of quantities as functions of one or more independent variables called parameters. Parametric equations are commonly used to express the coordinates of the points that make up a geometric object, such as a curve or surface, in which case the equations are collectively called a parametric representation or parameterization of the object.