Question

If the coordinate at one end of diameter of the circle

x² + y² – 8x – 4y + c = 0 are (–3,2), the coordinate at the other end are–

• A. (5, 3)
• B. (6, 2)
• C. (1, –8)
• D. (11, 2)

Answer 1

Answer: (D)

(11, 2)

Answer 2

Centre (4, 2)

$\frac{\alpha - 3}{2}$= 4 ̃ a = 11

$\frac{\beta + 2}{2}$ = 2 ̃ b = 2