Question

If the condenser shown in the circuit is charged to 5V and left in the circuit, in 12 sec the charge on the condenser will become - (e = 2.718)

• A. $\frac{10}{e}$coulomb
• B. $\frac{e}{10}$coulomb
• C. $\frac{10}{e^{2}}$coulomb
• D. $\frac{e^{2}}{10}$coulomb

Answer 1

Answer: (A)

$\frac{10}{e}$coulomb

Answer 2

q = q₀e^–t/t where q₀ = CV = 2 × 5 = 10 C

= CR = 2 × 6 = 12 s

q = 10 = coulomb