If the concentration of glucose ((C\_{6}H\_{12}O\_{6})) in b... | Chemistry | SolveeIt

Question

If the concentration of glucose $(C_{6}H_{12}O_{6})$ in blood is $0.9\, g\, L^{-1}$ , what will be the molarity of glucose in blood?

$5\, M$

$50\, M$

$0.005\, M$

$0.5\, M$

Answer

$0.005\, M$

Explanation

Solution

Molarity $= \frac {W_B (in\, g)}{M_B( in \, g\, mol^{-1}) \times {\text{ Volume of solution (in$ L $)}}}$ $\frac {Conc. (in \,g\, L^{-1})}{M_B (in \,g\, mol^{-1})} = \frac{0.9}{180} = 0.005\,M$ ( $\therefore$ Molar mass of $C_6H_{12}O_6=180\,g\,mol^{-1}$ )

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