Question
Question: If the complex number \(\dfrac{{8 - i}}{{3 - 2i}}\) is rewritten in the form of (a + ib), where a is...
If the complex number 3−2i8−i is rewritten in the form of (a + ib), where a is the real part and b is the imaginary part, then what is the value of a? (Use i = −1)
(a) 2 (b) 38 (c) 3 (d) 311
Solution
Hint – In this question rationalize the given complex number by multiplying the numerator and the denominator part by conjugate of the original denominator that is 3+2i. Then after simplification compare with the standard form of (a+ib), to get the value of a.
Complete step-by-step answer:
Given complex number is
3−2i8−i
Now first convert this in the form of (a + ib).
So, first rationalize the complex number, (i.e. multiply and divide by (3 + 2i) in the given complex number) we have,
⇒3−2i8−i×3+2i3+2i
Now multiply the numerator and in denominator apply the rule [(a−b)(a+b)=a2−b2]
⇒9−4i224−3i+16i−2i2
Now as we know in complex the value of [i2=−1] so, use this property in above equation we have,
⇒9−4(−1)24−3i+16i−2(−1)
Now simplify the above equation we have,
⇒9+424+13i+2=1326+13i=2+i
So this is the required form.
⇒2+i=a+ib
So on comparing we have,
a=2,b=1
Therefore, a = 2
So, this is the required answer.
Hence option (A) is correct.
Note – The real and imaginary part of a complex number is of great significance as it helps in plotting a complex number in the argand plane. The real part is plotted on the real axis whereas the imaginary part is plotted upon the complex axis. That’s why we express a complex number in terms of real and imaginary parts separately.