Question
Question: If the coefficients of second, third and fourth term in the expansion of \((1 + x)^{2n}\) are in A.P...
If the coefficients of second, third and fourth term in the expansion of (1+x)2n are in A.P., then 2n2−9n+7 is equal to
A
–1
B
0
C
1
D
3/2
Answer
0
Explanation
Solution
T2=2n⥂C1, T3=2n⥂C2,T4=2n⥂C3 are in A.P. then,
2.2n⥂C2=2n⥂C1+2n⥂C3
2.2.12n(.2n−1)=12n+3.2.12n(2n−1)(2n−2)
On solving, 2n2−9n+7=0