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Question

Physics Question on Transformers

If the coefficient of mutual induction of the primary and secondary coils of an induction coil is 5H5\, H and a current of 10A10 A is cut-off in 5×104s5 \times 10^{-4} s, the emf inducted (in volt) in the secondary coil is :

A

5×1045 \times 10^{4}

B

1×1051 \times 10^{5}

C

25×10525 \times 10^{5}

D

5×1065 \times 10^{6}

Answer

1×1051 \times 10^{5}

Explanation

Solution

The induced emf ee in the secondary is given by
e=dϕdt=MdIdte=-\frac{d \phi}{d t}=-M \frac{d I}{d t}
Or e=MdIdt|e|=M \frac{d I}{d t}
e=5×105×104\therefore |e| =5 \times \frac{10}{5 \times 10^{-4}}
=1×105V=1 \times 10^{5} \,V