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Question

Question: If the circumference of base of a hemisphere is \[2\pi \] then its volume ……………….\[c{m^3}\] A. \[\...

If the circumference of base of a hemisphere is 2π2\pi then its volume ……………….cm3c{m^3}
A. 2π3r3\dfrac{{2\pi }}{3}{r^3}
B. 2π3\dfrac{{2\pi }}{3}
C. 8π3\dfrac{{8\pi }}{3}
D. π12\dfrac{\pi }{{12}}

Explanation

Solution

Hint: The volume of the hemisphere is given by 2π3r3\dfrac{{2\pi }}{3}{r^3} , where ‘rr’ is the radius of the hemisphere. Circumference of the hemisphere is given by 2πr2\pi r, where ‘rr’ is the radius of the hemisphere. So, use this concept to reach the solution of the problem.

Complete step-by-step answer:

Given the circumference of base of a hemisphere is 2π2\pi
But circumference of the hemisphere is given by 2πr2\pi r
By comparing the above data, we have

2πr=2π r=1cm  \Rightarrow 2\pi r = 2\pi \\\ \therefore r = 1cm \\\

So, the radius of the hemisphere is 1 cm.
Now, volume of the sphere is given by V=2π3r3V = \dfrac{{2\pi }}{3}{r^3}

V=2π3(1)3 V=2π3×1 V=2π3cm3  \Rightarrow V = \dfrac{{2\pi }}{3}{\left( 1 \right)^3} \\\ \Rightarrow V = \dfrac{{2\pi }}{3} \times 1 \\\ \therefore V = \dfrac{{2\pi }}{3}c{m^3} \\\

Thus, the correct option is B. 2π3\dfrac{{2\pi }}{3}

Note: In math, a hemisphere is defined as a three-dimensional shape that’s half of a sphere with one flat, circular side. Always mention the units after writing the answer. Here the units of volume is cm3c{m^3}.