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Question: If the circle x<sup>2</sup> + y<sup>2</sup> + 4x + 22y + c = 0 bisects the circumference of the circ...

If the circle x2 + y2 + 4x + 22y + c = 0 bisects the circumference of the circle x2 + y2–2x + 8y – d = 0 then

c + d =

A

40

B

50

C

60

D

70

Answer

50

Explanation

Solution

Common chord is diameter of

x2 + y2 – 2x + 8y – d = 0

̃ 6x + 14y + c + d = 0 passer through (1, – 4)

̃ 6 (1) + 14(–4) + c + d = 0 ̃ c +d = 50