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Question

Question: If the chord \(y = mx + 1\) of the circle \(x^{2} + y^{2} = 1\)subtends an angle of measure 45<sup>o...

If the chord y=mx+1y = mx + 1 of the circle x2+y2=1x^{2} + y^{2} = 1subtends an angle of measure 45o at the major segment of the circle then value of m is

A

2

B

– 2

C

±\pm 1

D

None of these

Answer

±\pm 1

Explanation

Solution

Given circle is x2+y2=1,x^{2} + y^{2} = 1, C (0,0) and radius = 1 and chord is y=mx+1y = mx + 1

cos45o=CPCR\cos 45^{o} = \frac{CP}{CR}; CP = Perpendicular distance from (0, 0) to chord y=mx+1y = mx + 1

CP=1m2+1CP = \frac{1}{\sqrt{m^{2} + 1}} (CR = radius =1)

cos45o=1m2+1112=1m2+1\cos 45^{o} = \frac{\frac{1}{\sqrt{m^{2} + 1}}}{1} \Rightarrow \frac{1}{\sqrt{2}} = \frac{1}{\sqrt{m^{2} + 1}}

m2+1=2m=±1.m^{2} + 1 = 2 \Rightarrow m = \pm 1.