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Question: If the cathode–anode potential difference in an X-ray tube be 10<sup>5</sup> V, then the maximum ene...

If the cathode–anode potential difference in an X-ray tube be 105 V, then the maximum energy of X-ray photon can be.

A

105 J

B

105 MeV

C

10–1 MeV

D

105 KeV

Answer

10–1 MeV

Explanation

Solution

Since λ12375Vmin=12375105A˚=0.123A˚{\lambda\frac{12375}{V}}_{\min} = \frac{12375}{10^{5}}Å = 0.123Å

Ehcλminmax{E\frac{hc}{\lambda_{\min}}}_{\max}

On putting the values.

E1max{E - 1}_{\max}