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Question: If the binding energy of the deutrium is 2.23 MeV. The mass defect given in a.m.u. is....

If the binding energy of the deutrium is 2.23 MeV.

The mass defect given in a.m.u. is.

A

– 0.0024

B

– 0.0012

C

0.0012

D

0.0024

Answer

0.0024

Explanation

Solution

Mass defect Δm=2.23931\Delta m = \frac{2.23}{931}= 0.0024.