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Question: If the axis of a parabola and a rectangular hyperbola is same and the vertex of the parabola is same...

If the axis of a parabola and a rectangular hyperbola is same and the vertex of the parabola is same as the centre of rectangular hyperbola, then the locus of the point whose chord of contact with respect to the parabola touches the rectangular hyperbola is a/an-

A

Ellipse

B

Hyperbola

C

Circle

D

Parabola

Answer

Ellipse

Explanation

Solution

Let the parabola be y2 = 4ax and the rectangular hyperbola be x2 – y2 = a2. Let P(h, k) be the point whose chord of contact with respect to the parabola y2 = 4ax touches the rectangular hyperbola. The chord of contact of tangents from P(h, k) to the parabola y2 = 4ax is

ky = 2a (x + h)

Ž 2ax – ky + 2ah = 0 … (1)

This touches the rectangular hyperbola x2 – y2 = a2. So, it should be of the form

x sec q – y tan q = a … (2)

From equations (1) and (2), we get

2asecθ\frac{2a}{\sec\theta} = ktanθ\frac{- k}{- \tan\theta} = 2aha\frac{2ah}{- a}

Ž sec q = – ah\frac{a}{h} and tan q = – k2h\frac{k}{2h}

Ž sec2 q – tan2 q = a2h2\frac{a^{2}}{h^{2}}k24h2\frac{k^{2}}{4h^{2}}

Ž 1 = a2h2\frac{a^{2}}{h^{2}}k24h2\frac{k^{2}}{4h^{2}}

Ž 4h2 + k2 = 4a2

\ The locus of (h, k) is 4x2 + y2 = 4a2 which represents an ellipse with centre at (0, 0) and axes same as that of the hyperbola x2 – y2 = a2.

Hence (1) is correct answer.