Question

If the area of the parallelogram with $\vec{a}$ and $\vec{b}$ as two adjacent sides is $15$ s units then the area of the parallelogram having $3 \vec{a}+2 \vec{b}$ and $\vec{a}+3 \vec{b}$ as two adjacent sides in s units is

• A. 45
• B. 75
• C. 105
• D. 120

Answer 1

Answer: (C)

105

Answer 2

$|\vec{ a } \times \vec{ b }|=15$ $|(3 \vec{ a }+2 \vec{ b }) \times(\vec{ a }+3 \vec{ b })|$ $=|9(\vec{ a }+\vec{ b }) \times 2(\vec{ b }+\vec{ a })|$ $=|7(\vec{ a } \times \vec{ b })|=7 \times 15=105$