Question

If the area above the x-axis, bounded by the curves y =2^kx and x = 0 and x = 2 is $\frac { 3 } { \log 2 }$, then the value of k is -

• A. $\frac { 1 } { 2 }$
• B. 1
• C. –1
• D. 2

Answer 1

Answer: (B)

1

Answer 2

Area =

̃ $\left( 2 ^ { \mathrm { kx } } / ( \ln 2 ) \mathrm { k } \right) _ { 0 } ^ { 2 } = 3 / \log 2$

̃ 2^2k = 3k + 1 ̃ k = 1