Question

If the anions (1) form hexagonal closest packing and cations(3) occupy only 2/3 octahedral voids in it, then the general formula of the compound is

• A. CA
• B. CA2
• C. C2A3
• D. C3A2

Answer 1

Answer: (C)

C2A3

Answer 2

No. of A atoms = 6.

No. of C atoms = 6×$\frac{2}{3}$ = 4.

$\therefore$ Formula = C4A6 or C2A3.