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Question

Mathematics Question on Trigonometric Functions

If the angle between the hands of a clock be 5454^{\circ} and the time it reads between 77 and 88, find the time indicated by the clock.

A

7:487 : 48

B

7:307 : 30

C

7:257 : 25

D

7:407 : 40

Answer

7:487 : 48

Explanation

Solution

When the clock reads 7O7'O clock, the angle between the two hands is 7×30=2107 \times 30^{\circ} = 210^{\circ}. If the required time is 77 hours xx minutes, then we must have 210+x60×306x=±54210^{\circ}+\frac{x}{60}\times30^{\circ}-6x^{\circ}=\pm 54^{\circ} As the hour hand revolves 3030^{\circ} in one hour and minute hand revolves 360360^{\circ} in one hour, i.e., 66^{\circ} in one minute. 210+x26x±54\therefore 210+\frac{x}{2}-6x \pm 54 11x2=210±54\Rightarrow -\frac{11x}{2}=-210 \pm 54 =264=-264 or 156-156 x=48\Rightarrow x=48 or x=31211x=\frac{312}{11} But 31211\frac{312}{11} is not a whole number and clock cannot read this time, therefore, the time shown by the clock is 7:487 : 48.