Solveeit Logo

Question

Question: If the amplitude of sound is doubled and the frequency reduced to one-fourth, the intensity of sound...

If the amplitude of sound is doubled and the frequency reduced to one-fourth, the intensity of sound at the same point will be

A

Increased by a factor of 2

B

Decreased by a factor of 2

C

Decreased by a factor of 4

D

Unchanged

Answer

Decreased by a factor of 4

Explanation

Solution

I=2π2a2n2vρI = 2\pi^{2}a^{2}n^{2}v\rhoIa2n2I \propto a^{2}n^{2}I1I2=(a1a2)2×(n1n2)2\frac{I_{1}}{I_{2}} = \left( \frac{a_{1}}{a_{2}} \right)^{2} \times \left( \frac{n_{1}}{n_{2}} \right)^{2}

=(12)2×(11/4)2I2=I14= \left( \frac{1}{2} \right)^{2} \times \left( \frac{1}{1/4} \right)^{2} \Rightarrow I_{2} = \frac{I_{1}}{4}

(I=2π2a2n2vρI = 2\pi^{2}a^{2}n^{2}v\rhoIa2n2I \propto a^{2}n^{2}I1I2=(a1a2)2×(n1n2)2\frac{I_{1}}{I_{2}} = \left( \frac{a_{1}}{a_{2}} \right)^{2} \times \left( \frac{n_{1}}{n_{2}} \right)^{2}

=(12)2×(11/4)2I2=I14= \left( \frac{1}{2} \right)^{2} \times \left( \frac{1}{1/4} \right)^{2} \Rightarrow I_{2} = \frac{I_{1}}{4})