Question
Question: If the 4<sup>th</sup> term in the expansion of \(\left( ax + \frac{1}{x} \right)^{n}\) is \(\frac{5}...
If the 4th term in the expansion of (ax+x1)n is 25, then the value of a & n are –
A
21, 6
B
1, 3
C
21, 31
D
Can not be found
Answer
21, 6
Explanation
Solution
T4 = nC3 (ax)n–3 (x1)3 = 25 (independent of x)
\ xn–6 = x0
i.e. n = 6
& 6C3 a3 = 25
Ž a = 21