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Question: If the 4<sup>th</sup> term in the expansion of \(\left( ax + \frac{1}{x} \right)^{n}\) is \(\frac{5}...

If the 4th term in the expansion of (ax+1x)n\left( ax + \frac{1}{x} \right)^{n} is 52\frac{5}{2}, then the value of a & n are –

A

12\frac{1}{2}, 6

B

1, 3

C

12\frac{1}{2}, 13\frac{1}{3}

D

Can not be found

Answer

12\frac{1}{2}, 6

Explanation

Solution

T4 = nC3 (ax)n–3 (1x)3\left( \frac{1}{x} \right)^{3} = 52\frac{5}{2} (independent of x)

\ xn–6 = x0

i.e. n = 6

& 6C3 a3 = 52\frac{5}{2}

Ž a = 12\frac{1}{2}