Question
Question: If the 3rd term in the expansion of (x +x<sup>t</sup>)<sup>5</sup> is 10<sup>6</sup> where t = log<s...
If the 3rd term in the expansion of (x +xt)5 is 106 where t = log10 x then the number of possible values of x is
A
2
B
0
C
1
D
Infinite
Answer
2
Explanation
Solution
T3 = 5C2 x3+2t = 106 Ž x3+2t = 105
Ž (3 + 2t)t = 5 Ž t = 1, –5/2
Ž x = 10, 10–5/2