Solveeit Logo

Question

Mathematics Question on Arithmetic Progression

If the (2p)th(2p)^{th} term of a H.P. is qq and the (2q)th(2q)^{th} term is pp, then the 2(p+q)th2(p + q)^{th} term is-

A

pq2(p+q)\frac{pq}{2(p + q)}

B

pqp+q\frac{pq}{p + q}

C

2pqp+q\frac{2pq}{p + q}

D

p+qpq\frac{p + q}{pq}

Answer

p+qpq\frac{p + q}{pq}

Explanation

Solution

If aa is the first term and dd is the common difference of the associated A.P.
1q=1a+(2p1)d,1p=1a+(2q1)d\frac{1}{q} = \frac{1}{a} +\left(2p-1\right)d, \frac{1}{p} = \frac{1}{a} +\left(2q-1\right)d
d=12pq\Rightarrow d = \frac{1}{2pq}
If hh is the 2(p+q)th2\left(p+q\right)^{th} term 1h=1a+(2p+2q1)d \frac{1}{h}=\frac{1}{a} + \left(2p + 2q - 1\right)d
=1q+1p=p+qpq= \frac{1}{q} + \frac{1}{p} = \frac{p+q}{pq}