Question
Mathematics Question on types of differential equations
If θ+Φ=90°,θ-Φ=30°,then sin θ+sin Φ=
A
sin θ+cos θ
B
sin Φ+cos Φ
C
sin θ+cos Φ
D
cos θ+cos Φ
Answer
sin θ+cos θ
Explanation
Solution
The correct option is: A, B and D
If θ+Φ=90°,θ-Φ=30°,then sin θ+sin Φ=
sin θ+cos θ
sin Φ+cos Φ
sin θ+cos Φ
cos θ+cos Φ
sin θ+cos θ
The correct option is: A, B and D