Question

If temperature of gas increases from 27C to 927C the K.E. will be

• A. Double
• B. Half
• C. One fourth
• D. Four times

Answer 1

Answer: (D)

Four times

Answer 2

Kinetic energy µ Temperature

Ž $\frac{E_{1}}{E_{2}} = \frac{T_{1}}{T_{2}}$ Ž $\frac{E_{1}}{E_{2}} = \frac{(273 + 27)}{(273 + 927)} = \frac{300}{1200} = \frac{1}{4}$

Ž $E_{2} = 4E_{1}$