Question

If $\tan\theta + \tan 2\theta + \sqrt{3}\tan\theta\tan 2\theta = \sqrt{3}$ then $\tan\theta + \tan 2\theta = \sqrt{3}(1 - \tan\theta\tan 2\theta)$

• A. $\frac{\tan\theta + \tan 2\theta}{1 - \tan\theta\tan 2\theta}$
• B. $\sqrt{3}$
• C. $\tan 3\theta = \tan(\pi/3)$
• D. $3\theta = n\pi + \frac{\pi}{3}$

Answer 1

Answer: (A)

$\frac{\tan\theta + \tan 2\theta}{1 - \tan\theta\tan 2\theta}$

Answer 2

We have $\frac { \pi } { 4 } \cot \theta = \frac { \pi } { 2 } - \frac { \pi } { 4 } \tan \theta$

$\Rightarrow$

$\frac{\sin^{2}\theta}{\cos\theta} + \sqrt{3}\tan\theta = 0$ $\Rightarrow$.