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Question: If tan<sup>–1</sup> x + tan<sup>–1</sup> y + tan<sup>–1</sup> z = p, then ![](https://cdn.pureessenc...

If tan–1 x + tan–1 y + tan–1 z = p, then + 1yz\frac { 1 } { \mathrm { yz } } + =

A

0

B

1

C

1/xyz

D

xyz

Answer

1

Explanation

Solution

Ž tan–1 x + tan–1y = p – tan–1z

Ž x +y/1–xy = – z

Ž x + y + z = xyz

divide by xyz, we get 1/xy + 1/yz + 1/zx = 1