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Question

Question: If tan<sup>–1</sup> x + cos<sup>–1</sup>\(\frac{y}{\sqrt{1 + y^{2}}}\)= sin<sup>–1</sup>\(\frac{3}{\...

If tan–1 x + cos–1y1+y2\frac{y}{\sqrt{1 + y^{2}}}= sin–1310\frac{3}{\sqrt{10}}where x and y are +ve

integer, then number of possible pair of (x, y) is-

A

1

B

2

C

3

D
Answer

2

Explanation

Solution

tan–1 x + tan–1 1y\frac{1}{y}= tan–1 3

̃ xy+1yx\frac{xy + 1}{y - x}= 3 or, y = 3x+13x\frac{3x + 1}{3 - x}

y > 0 ̃ 3x+13x\frac{3x + 1}{3 - x}> 0

̃ – 13\frac{1}{3}< x < 3

\ x = 1, 2 and corresponding values of y are 2, 7. Hence two pairs (1, 2) and (2, 7) are possible.