Question
Question: If \(\tan \theta + \tan 4\theta + \tan 7\theta = \tan \theta \tan 4\theta \tan 7\theta \) then the g...
If tanθ+tan4θ+tan7θ=tanθtan4θtan7θ then the general solution is :-
A.θ=4nπ B.θ=12nπ C.θ=6nπ D. None of these
Solution
Hint : Use the formula tan(a+b+c) and consider a,b,c as θ,4θ,7θ. Here remembering the trigonometric formula is a key point.
The given equation is
tanθ+tan4θ+tan7θ=tanθtan4θtan7θ
After transposing we get,
tanθ+tan4θ+tan7θ−tanθtan4θtan7θ=0 ............(i)
As we know
tan(a+b+c)=1−tanatanb−tanatanc−tanbtanctana+tanb+tanc−tanatanbtanc ...........(ii)
Use the above equation for the given equation we get,
tan(θ+4θ+7θ)=1−tanθtan4θ−tanθtan7θ−tan7θtan4θtanθ+tan4θ+tan7θ−tanθtan4θtan7θ = tan(12θ) ...........(iii)
But from equation (i) we say the numerator of equation (iii) is zero.
Therefore,
tan(12θ)=0 12θ=nπ θ = 12nπ
Hence the correct option is B.
Note :- In these types of questions of finding general values of angles we have to think , which trigonometric formula fits into the given equation so that the problem is solved. Then we have to use quadrant rules to write the general values of angles.