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Question

Question: If \( \tan \theta =\sqrt{2} \) , then the value of \( \theta \) is: a). less than \( \dfrac{\pi }{...

If tanθ=2\tan \theta =\sqrt{2} , then the value of θ\theta is:
a). less than π4\dfrac{\pi }{4}
b). equal to π4\dfrac{\pi }{4}
c). between π4\dfrac{\pi }{4} and π3\dfrac{\pi }{3}
d). greater than π3\dfrac{\pi }{3}

Explanation

Solution

To solve the question like above we will iterate through each of the above options and then check every option and the option which satisfies our question is the correct answer. We will also use the value of tanπ4=1\tan \dfrac{\pi }{4}=1 , tanπ3=3\tan \dfrac{\pi }{3}=\sqrt{3} .

Complete step-by-step answer:
Since, we have to find the value of θ\theta for which tanθ=2\tan \theta =\sqrt{2} . To solve the question, we will iterate through each option.
Also, tanθ=2=1.414\tan \theta =\sqrt{2}=1.414
So, Option (a): It states that θ\theta is less than π4\dfrac{\pi }{4} , and we know that tanπ4=1\tan \dfrac{\pi }{4}=1 , so we can say that if θ\theta is less than π4\dfrac{\pi }{4} , then tanθ\tan \theta must be less than 1 because tanθ\tan \theta is an increasing function between (0,π2)\left( 0,\dfrac{\pi }{2} \right) .
But, it is given in the question that tanθ=2=1.414\tan \theta =\sqrt{2}=1.414 , which is greater than 1 so θ\theta can’t be less than π4\dfrac{\pi }{4} .
Hence, option (a) is incorrect.
Option (b): It states that θ\theta is equal to π4\dfrac{\pi }{4} . And, we have seen above in option (a) that tanπ4=1\tan \dfrac{\pi }{4}=1 , but we have to find θ\theta for which tanθ=2=1.414\tan \theta =\sqrt{2}=1.414 . So, option (b) is also incorrect.
Option (c): It states that θ\theta is between π4\dfrac{\pi }{4} and π3\dfrac{\pi }{3} . And, we know that tanπ4=1\tan \dfrac{\pi }{4}=1 and tanπ3=3=1.732\tan \dfrac{\pi }{3}=\sqrt{3}=1.732 so, we can say that tanθ\tan \theta must lies in between 1 and 1.732.
And, we have to find the value of θ\theta for which tanθ=2=1.414\tan \theta =\sqrt{2}=1.414 and since 1.414 lies between 1 and 1.732. So, we can say that tanθ\tan \theta must lies between π4\dfrac{\pi }{4} and π3\dfrac{\pi }{3} if tanθ=2\tan \theta =\sqrt{2} .
Hence, option (c) is our correct option.
Option (d): It states that θ\theta greater than π3\dfrac{\pi }{3} . And, we know that tanπ3=3=1.732\tan \dfrac{\pi }{3}=\sqrt{3}=1.732 , so we can say that tanθ\tan \theta must be greater than 1.732 but we have to find such θ\theta for which tanθ=2=1.414\tan \theta =\sqrt{2}=1.414 , and we can see that 1.414 is less than 1.732. So, θ\theta can’t be greater than π3\dfrac{\pi }{3} . So, option (d) is incorrect.
Hence, the correct option is only (c). This is our required answer.

So, the correct answer is “Option (c)”.

Note: Students are required to note that we directly do not know the value of θ\theta for which tanθ=2\tan \theta =\sqrt{2} from the normal trigonometric table which we generally remember. So, we can only calculate the range of the values, not the exact value.