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Question

Question: If \(\tan \theta =2\), how do you find the value of \({{\tan }^{3}}\theta \)?...

If tanθ=2\tan \theta =2, how do you find the value of tan3θ{{\tan }^{3}}\theta ?

Explanation

Solution

In this problem we have the value of tanθ\tan \theta and asked to calculate the value of tan3θ{{\tan }^{3}}\theta . We can say that the value of tan3θ{{\tan }^{3}}\theta is the tanθ\tan \theta times of tan2θ{{\tan }^{2}}\theta and the value of tan2θ{{\tan }^{2}}\theta is the tanθ\tan \theta times of the tanθ\tan \theta . So, to calculate the value of tan3θ{{\tan }^{3}}\theta , we will first calculate the value of tan2θ{{\tan }^{2}}\theta . We can calculate the value of tan2θ{{\tan }^{2}}\theta by multiplying the tanθ\tan \theta with the tanθ\tan \theta and simplify the obtained value to get the value of tan2θ{{\tan }^{2}}\theta . After getting the value of tan2θ{{\tan }^{2}}\theta , we will again multiply it with tanθ\tan \theta to get the value of tan3θ{{\tan }^{3}}\theta . Now we will simplify the obtained equation, then we will get the required result.

Complete step by step answer:
Given that, tanθ=2\tan \theta =2.
Now the value of tan2θ{{\tan }^{2}}\theta can be calculated by multiplying tanθ\tan \theta with the same tanθ\tan \theta . So, multiplying tanθ\tan \theta with tanθ\tan \theta , then we will get
tanθ×tanθ=2×2\Rightarrow \tan \theta \times \tan \theta =2\times 2
Simplifying the above equation, then we will get
tan2θ=4\Rightarrow {{\tan }^{2}}\theta =4.
Now we have the value of tan2θ{{\tan }^{2}}\theta as tan2θ=4{{\tan }^{2}}\theta =4. For calculating the value of tan3θ{{\tan }^{3}}\theta we are going to multiply the above tan2θ{{\tan }^{2}}\theta value with the tanθ\tan \theta value, then we will get
tan2θ×tanθ=4×2\Rightarrow {{\tan }^{2}}\theta \times \tan \theta =4\times 2
Simplifying the above equation, then we will get
tan3θ=8\Rightarrow {{\tan }^{3}}\theta =8.

Hence the value of tan3θ{{\tan }^{3}}\theta when tanθ=2\tan \theta =2 is 88.

Note: We can also calculate the above value in another method. We can do cubing on the both sides for the value tanθ=2\tan \theta =2, then we will get
(tanθ)3=(2)3\Rightarrow {{\left( \tan \theta \right)}^{3}}={{\left( 2 \right)}^{3}}
Simplifying the above equation, then we will get
tan3θ=8\Rightarrow {{\tan }^{3}}\theta =8
From both the methods we got the same result.