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Question

Question: If sum of *n* terms of an A.P. is \(3n^{2} + 5n\) and \(T_{m} = 164\), then *m* =...

If sum of n terms of an A.P. is 3n2+5n3n^{2} + 5n and Tm=164T_{m} = 164, then

m =

A

26

B

27

C

28

D

None of these

Answer

27

Explanation

Solution

Tm=SmSm1T_{m} = S_{m} - S_{m - 1}164=(3m2+5m){3(m1)2+5(m1)}164 = (3m^{2} + 5m) - \{ 3(m - 1)^{2} + 5(m - 1)\}

164=3(2m1)+5164 = 3(2m - 1) + 5m=27m = 27