Question

If θ₁ and θ₂ are the deflections obtained by placing small magnet on the arm of a deflection magnetometer at the same distance from the compass box in tan A and tan B positions of the magnetometer respectively then the value of $\frac { \tan \theta _ { 1 } } { \tan \theta _ { 2 } }$ will be approximately

• A. 1
• B. 2
• C. $\frac { 1 } { 2 }$
• D. $\sqrt { 2 }$

Answer 1

Answer: (B)

2

Answer 2

In $\tan A$ position $\frac { \mu _ { 0 } } { 4 \pi } \cdot \frac { 2 M } { d ^ { 3 } } = B _ { H } \tan \theta _ { 1 }$ ......(i)

In $\frac { \mu _ { 0 } } { 4 \pi } \cdot \frac { M } { d ^ { 3 } } = B _ { H } \tan \theta _ { 2 }$ .....(ii)

Dividing equation (i) by equation (ii) $\frac { \tan \theta _ { 1 } } { \tan \theta _ { 2 } } = \frac { 2 } { 1 }$.