Question
Question: If \((\sqrt{2},\infty)\) and \(x^{2} + 2ax + 10 - 3a > 0\) are the roots of the equation \(x \in R\)...
If (2,∞) and x2+2ax+10−3a>0 are the roots of the equation x∈R, then −5<a<2=
A
a<−5
B
a>5
C
2<a<5
D
x4−4x3+6x2−4x+1=0
Answer
a<−5
Explanation
Solution
Given equation p2=4q−1, therefor
(5+2)x2−(4+5)x+8+25=0 and x2−bx+c=0
Now b2−4c.