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Question: If \(\sqrt{- 1}\) = \(a = 2 , b = 4\) and \(\left[ \begin{array} { l l l } x & y & z \end{array} \ri...

If 1\sqrt{- 1} = a=2,b=4a = 2 , b = 4 and [xyz][ahghbfgfc][xyz]\left[ \begin{array} { l l l } x & y & z \end{array} \right] \left[ \begin{array} { l l l } a & h & g \\ h & b & f \\ g & f & c \end{array} \right] \left[ \begin{array} { l } x \\ y \\ z \end{array} \right] is a non real cube root of unity then the

value of 1ω21+i+ω2i11i+ω1iω211\left| \begin{matrix} 1 & \omega^{2} & 1 + i + \omega^{2} \\ –i & - 1 & - 1 - i + \omega \\ 1 - i & \omega^{2} - 1 & - 1 \end{matrix} \right|is equal to :

A

1

B

ii

C

ω\omega

D

0

Answer

0

Explanation

Solution

R1 → R1 + R2 – R3

= $\left| \begin{matrix} 0 & 0 & 1 + \omega + \omega^{2} \

  • i & - 1 & - 1 - i + \omega \ 1 - i & \omega^{2} - 1 & - 1 \end{matrix} \right|$

= $\left| \begin{matrix} 0 & 0 & 0 \

  • i & - 1 & - 1 - i + \omega \ 1 - i & \omega^{2} - 1 & - 1 \end{matrix} \right|$ = 0