Question

If spheres of radius $'r'$ are arranged in ccp fashion (ABCABC.....), the vertical distance between any two consecutive A layers is

• A. $4 r \sqrt{\frac{2}{3}}$
• B. $4 r \sqrt{\frac{3}{2}}$
• C. 6r
• D. $e \sqrt{6}$

Answer 1

Answer: (A)

$4 r \sqrt{\frac{2}{3}}$

Answer 2

Distance between two consecutive A layers (d) $= 2 \sqrt{\frac{2}{3}} a$ But $a = 2 r$ $\therefore \, d = 2 \sqrt{\frac{2}{3}} \times 2r = 4 r \sqrt{\frac{2}{3}}$