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Question: If Sohail pays ₹ 1.30 for using Prabhu’s money from 2nd January to 7th January at 3% per month, how ...

If Sohail pays ₹ 1.30 for using Prabhu’s money from 2nd January to 7th January at 3% per month, how much loan had Sohail taken from Prabhu?

Explanation

Solution

Hint: Amount = ₹ 1.30, N= 6 days, R= 3365%\dfrac{3}{{365}}\% , let principal amount be x.
While calculating simple interest by days, use the number of days for N and divide the interest rate by 365.
Also, Amount (A) = Principal amount (P) + Simple Interest (S.I) and Simple Interest = P×N×R100\dfrac{{P \times N \times R}}{{100}}

Complete step-by-step answer:
We will first calculate simple interest
S.I=x×6×3365100\therefore S.I = \dfrac{{x \times 6 \times \dfrac{3}{{365}}}}{{100}}
=x×6×3100×365= \dfrac{{x \times 6 \times 3}}{{100 \times 365}}
Now we will Multiply the product of 6 & 3 and 365 & 100
S.I=18x36500\therefore S.I = \dfrac{{18x}}{{36500}}

Now we will find the quotient of 10 & 36500 to find S.I
S.I=0.00049x\therefore S.I = 0.00049x …… (1)
Now we will substitute the value of S.I from equation 1 in the formula of Amount
1.30=x+0.00049x\therefore 1.30 = x + 0.00049x
Now we will add the coefficient of x
1.30=1.00049x   \therefore 1.30 = 1.00049x \\\ \\\
Now we will find the quotient of 1.30 & 1.00049 to find x which is the principal amount
x=1.301.00049x = \dfrac{{1.30}}{{1.00049}}
x=1.2994\therefore x = 1.2994
Hence, Sohail has taken a loan amount of ₹ 1.2994 from Prabhu.

Note: Avoid understanding the amount ₹ 1.30 as the principal amount. The principal amount and amount are different.