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Question: If \(\sin\theta = \frac{24}{25}\)and \(\theta\) lies in the second quadrant, then \(\sec\theta + \ta...

If sinθ=2425\sin\theta = \frac{24}{25}and θ\theta lies in the second quadrant, then secθ+tanθ=\sec\theta + \tan\theta =

A

– 3

B

– 5

C

– 7

D

– 9

Answer

– 7

Explanation

Solution

sinθ=2425cosθ=725,tanθ=247\sin\theta = \frac{24}{25} \Rightarrow \cos\theta = \frac{- 7}{25},\tan\theta = \frac{- 24}{7}

\therefore secθ+tanθ=257+247=7\sec\theta + \tan\theta = \frac{- 25}{7} + \frac{- 24}{7} = - 7