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Question

Mathematics Question on Trigonometric Functions

If sinA=35sinA=\frac{3}{5} and AA is in first quadrant, then the values of sin2Asin2A, cos2Acos2A and tan2Atan2A are

A

24/2524/25, 7/257/25, 24/724/7

B

1/251/25, 7/257/25, 1/71/7

C

24/2524/25, 1/251/25, 24/724/7

D

1/251/25, 24/2524/25, 1/241/24

Answer

24/2524/25, 7/257/25, 24/724/7

Explanation

Solution

We have, sinA=35sinA=\frac{3}{5} cosA=1sin2A=1925\Rightarrow cosA=\sqrt{1-sin^{2}\,A}=\sqrt{1-\frac{9}{25}} =1625=45=\sqrt{\frac{16}{25}}=\frac{4}{5} and tanA=sinAcosA=3/54/5=34tanA=\frac{sin\,A}{cos\,A}=\frac{3/5}{4/5}=\frac{3}{4} Now, sin2A=2sinAcosAsin2A=2sinA\cdot cosA =2×35×45=2425=2\times\frac{3}{5}\times\frac{4}{5} =\frac{24}{25} cos2A=12sin2A=725cos2A=1-2sin^{2}A=\frac{7}{25} and tan2A=247tan2A=\frac{24}{7}