Question

If sin⁡θ=2t1+t2 and θ lies in the second quadrant, then cos⁡θ is equal to

• A. (A) 1−t21+t2
• B. (B) t2−11+t2
• C. (C) −|1−t2|1+t2
• D. (D) 1+t2|1−t2|

Answer 1

Answer: (C)

(C) −|1−t2|1+t2

Answer 2

Explanation:
θ in 2nd quad Cosθ < 0|cos⁡θ|=|1−t21+t2|=|1−t2|1+t2cos⁡θ=−|1−t2|1+t2