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Question

Mathematics Question on Trigonometric Equations

If sin β is the GM between sin a and cos a, then cos 2β is equal to

A

2sin2=(π4a)2sin^2=(\frac{\pi}{4}-a)

B

2cot2=(π4a)2cot^2=(\frac{\pi}{4}-a)

C

2cos2=(π4a)2cos^2=(\frac{\pi}{4}-a)

D

2sin2=(π4+a)2sin^2=(\frac{\pi}{4}+a)

Answer

2sin2=(π4a)2sin^2=(\frac{\pi}{4}-a)

Explanation

Solution

The correct answer is(A): 2sin2=(π4a)2sin^2=(\frac{\pi}{4}-a)