Question

If sides of a triangle are in A.P. and (a – b + c) s = kb² (where s is the semi perimeter) then k is equal to

• A. 17
• B. 3
• C. $\frac { 1 - \sqrt { 3 } } { 2 }$
• D. $\frac { 3 } { 2 }$

Answer 1

Answer: (D)

$\frac { 3 } { 2 }$

Answer 2

2b = a + c

Now, (a + c –b) s = kb²

Ž= kb² Ž $\frac { 3 b ^ { 2 } } { 2 }$ = kb² Ž k = $\frac { 3 } { 2 }$