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Question: If separation of two energy levels in an atom is 2.3 eV, then the frequency of radiation emitted whe...

If separation of two energy levels in an atom is 2.3 eV, then the frequency of radiation emitted when the atom transits from the upper level to the lower level is

A

2.6×1013 Hz2.6 \times 10^{13}\text{ Hz}

B

5.6×1014 Hz5.6 \times 10^{14}\text{ Hz}

C

5.6×1018 Hz5.6 \times 10^{18}\text{ Hz}

D

2.6×1018 Hz2.6 \times 10^{18}\text{ Hz}

Answer

5.6×1014 Hz5.6 \times 10^{14}\text{ Hz}

Explanation

Solution

Here ,

EU−EL=2.3eV=2.3eV=2.3×1.6×10−19JE_{U} - E_{L} = 2.3eV = 2.3eV = 2.3 \times 1.6 \times 10^{- 19}J

From third postulate of Bohr’s atomic model

hυ=EU−ELh\upsilon = E_{U} - E_{L}

Or υ=EU−ELh=2.3×1.6×10−196.64×10−34=5.6×1014Hz\upsilon = \frac{E_{U} - E_{L}}{h} = \frac{2.3 \times 1.6 \times 10^{- 19}}{6.64 \times 10^{- 34}} = 5.6 \times 10^{14}Hz