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Question

Mathematics Question on Trigonometry

If secθ=23\sec \theta = \frac{2}{\sqrt{3}},then cosθ=cosθ=

A

32\frac{\sqrt{3}}{2}

B

23\frac{2}{\sqrt{3}}

C

12\frac{1}{\sqrt{2}}

D

13\frac{1}{\sqrt{3}}

Answer

32\frac{\sqrt{3}}{2}

Explanation

Solution

The correct option is (A): 32\frac{\sqrt{3}}{2}