QuestionReportMathematics Question on TrigonometryIf secθ=23\sec \theta = \frac{2}{\sqrt{3}}secθ=32,then cosθ=cosθ=cosθ=A32\frac{\sqrt{3}}{2}23B23\frac{2}{\sqrt{3}}32C12\frac{1}{\sqrt{2}}21D13\frac{1}{\sqrt{3}}31Answer32\frac{\sqrt{3}}{2}23ExplanationSolutionThe correct option is (A): 32\frac{\sqrt{3}}{2}23