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Question

Mathematics Question on Trigonometric Identities

If sec θ+ tan θ= X, then tan θ =

A

x2+1x\frac{x^2+1}{x}

B

x2−1x\frac{x^2-1}{x}

C

x2+12x\frac{x^2+1}{2x}

D

x2−12x\frac{x^2-1}{2x}

Answer

x2−12x\frac{x^2-1}{2x}

Explanation

Solution

The correct option is (D): x2−12x\frac{x^2-1}{2x}