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Question: If \(\sec ^ { 2 } \theta = \frac { 4 } { 3 }\) then the general value of \(\theta\) is...

If sec2θ=43\sec ^ { 2 } \theta = \frac { 4 } { 3 } then the general value of θ\theta is

A

2nπ±π62 n \pi \pm \frac { \pi } { 6 }

B

nπ±π6n \pi \pm \frac { \pi } { 6 }

C

2nπ±π32 n \pi \pm \frac { \pi } { 3 }

D

nπ±π3n \pi \pm \frac { \pi } { 3 }

Answer

nπ±π6n \pi \pm \frac { \pi } { 6 }

Explanation

Solution

sec2θ=43\sec ^ { 2 } \theta = \frac { 4 } { 3 } cos2θ=34=(32)2\Rightarrow \cos ^ { 2 } \theta = \frac { 3 } { 4 } = \left( \frac { \sqrt { 3 } } { 2 } \right) ^ { 2 } cos2θ=cos2π6\Rightarrow \cos ^ { 2 } \theta = \cos ^ { 2 } \frac { \pi } { 6 }

θ=nπ±π6\therefore \theta = n \pi \pm \frac { \pi } { 6 } .