Question
Question: If \({S^o}\) for \({H_2},C{l_2}\) and \(HCl\) are 0.13, 0.22 and 0.19 \(kJ{K^{ - 1}}mo{l^{ - 1}}\) r...
If So for H2,Cl2 and HCl are 0.13, 0.22 and 0.19 kJK−1mol−1 respectively. The total change in standard entropy for the reaction
H2+Cl2→2HCl is:
A) 30JK−1mol−1
B) 40JK−1mol−1
C) 60JK−1mol−1
D) 20JK−1mol−1
Solution
We are given the standard entropy values for H2,Cl2 and HCl. The total change in standard entropy for any reaction is the difference between standard entropy for products and standard entropy for reactants.
Complete step by step solution:
Let us first write the given values in the question.
Standard entropy for H2 (SH2o)= 0.13 kJK−1mol−1.
Standard entropy for Cl2 (SCl2o) = 0.22 kJK−1mol−1.
Standard entropy for HCl (SHClo) = 0.19 kJK−1mol−1.
Given reaction is: H2+Cl2→2HCl
To find total change in standard entropy for the above reaction, we need to take the difference of the sum of standard entropy for products and sum of standard entropy for reactants.
Thus, we can also write, total change in standard entropy (ΔSo) as:ΔSo=∑nSo(products)−∑nSo(reactants)
Here, n is the stoichiometric coefficient before products and reactants.
In the given reaction, the product is HCl and H2and Cl2 are reactants.
Therefore, total change in standard entropy for the given reaction = 2(SHClo)−(SH2o+SCl2o) . (Here, 2 is the stoichiometric coefficient of HCl).
Total change in standard entropy for the given reaction = 2(0.19)−(0.13+0.22)=0.03KJK−1mol−1=30JK−1mol−1 .
Thus, option A is the correct answer.
Note: It should be known that entropy change for a chemical reaction can be determined if standard or absolute entropies of each substance are known. The standard entropy of a substance is given by the symbol Soand this is determined under standard conditions which are called STP conditions. The SI units for entropy are K−1mol−1. As the temperature of the substance increases, its entropy increases because of an increase in the randomness of the molecules within the system.