Question

If S = $\frac{1}{3}$ft³, 'f ' has the dimensions of –

• A. $\lbrack M^{0}L^{\text{-1}}T^{3}\rbrack$
• B. $\lbrack M^{1}L^{1}T^{\text{ -3}}\rbrack$
• C. $\lbrack M^{0}L^{1}\text{T}\text{ }^{\text{-3}}\rbrack$
• D. $\lbrack M^{0}L^{\text{-1}}\text{T}\text{ }^{\text{-3}}\rbrack$

Answer 1

Answer: (C)

$\lbrack M^{0}L^{1}\text{T}\text{ }^{\text{-3}}\rbrack$

Answer 2

$\text{f } = \ \frac{3S}{t^{3}}$

= $\frac{M^{0}L^{1}T^{0}}{T^{3}} = \lbrack L^{1}\text{T}\text{ }^{\text{-3}}\rbrack$